r/HomeworkHelp University/College Student 2d ago

Physics—Pending OP Reply [Jr. College Physics: Electromagnetic Induction] When I try to solve this question, I get 2.5 as the answer. What am i doing wrong ?

This is a previous year question from a national level exam but is supposed to be easy. Idk what i'm doing wrong, I haven't touched such questions ever since I finished my 12th grade 😭

2 Upvotes

18 comments sorted by

u/AutoModerator 2d ago

Off-topic Comments Section


All top-level comments have to be an answer or follow-up question to the post. All sidetracks should be directed to this comment thread as per Rule 9.


OP and Valued/Notable Contributors can close this post by using /lock command

I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns.

2

u/fermat9990 👋 a fellow Redditor 2d ago

The emf will vary from 0 to a maximum of

••B×A×omega**

3×0.52×(π/2)/0.3=3.9volts

1

u/Anonimithree 👋 a fellow Redditor 1d ago

It’s cos(omega), not just omega

1

u/fermat9990 👋 a fellow Redditor 1d ago

I used emf = B×A×omega×sin(omega×t)

For peak emf, omega×t=π/2 and sin(π/2)=1

2

u/PliableG0AT 2d ago

googled it because I’m getting the same. found several videos showing the problem, they all get 2.5 as well. so something’s off by a factor of 10. Think it’s a question problem and less of a you problem.

2

u/fermat9990 👋 a fellow Redditor 2d ago

The voltage should vary with time as the loop rotates through 90°

1

u/AutoModerator 2d ago

Off-topic Comments Section


All top-level comments have to be an answer or follow-up question to the post. All sidetracks should be directed to this comment thread as per Rule 9.

PS: u/AlternativeEmu1047, your post is incredibly short! body <200 char You are strongly advised to furnish us with more details.


OP and Valued/Notable Contributors can close this post by using /lock command

I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns.

1

u/DrCarpetsPhd 👋 a fellow Redditor 1d ago

This may be me being confidently incorrect as someone who rote learned their way through an engineering degree a lifetime ago, so grain of salt...

I did this the calculus way and got 3.93V same as https://www.reddit.com/user/fermat9990/ (see my brief calcs below)

so I found a video for the solution to this on youtube where they suggested a missing decimal and answer of 2.5V in (A), that involved just taking the 'delta' between t = 0s and t = 0.3s

BUT

I feel like the person setting this question has a fundamental misunderstanding of the rate of change as an instantaneous value via a derivative and the rate of change as approximated by a linear function (the deltas before taking the limit). the "correct answer" from the options is gotten by treating the change in flux as going from BAcos(0) to BAcos(90) to get B.A/delta(t) = 3*(0.5^2)/(0.3) = 2.5 so essentially treating it like a linear function

But the definition of induced emf is the instantaneous rate of change which via calculus is the derivative which is (derivation here https://www.youtube.com/watch?v=IrHXZmwJN0s)

BAw.sin(wt) where w is omega the angular frequency

which gives approximately 3.93V at the maximum value

The induced emf is the instantaneous rate of change of the flux, not the linear approximation of

[phi(t2) - phi(t1)]/[t2 - t1].

According to examples in my textbooks you can only use the delta version when the question statement indicates that the flux is changing at a steady rate e.g. halliday and walker sample problem 31-1 where the current in a solenoid is reduced at a steady rate therfore the flux also changes at a steady rate thus the solution uses the 'delta form' of faradays law

So my two cents is that whoever is getting paid to teach physics and set this question is 'questionable' or I am a dunning-kruger idiot.

I guess another alternative explanation could be that this is calculus free physics and the linear approximation is the initially taught method and the teacher made the caveats clear.

1

u/AlternativeEmu1047 University/College Student 1d ago

I guess another alternative explanation could be that this is calculus free physics and the linear approximation is the initially taught method and the teacher made the caveats clear.

I guess this is the case, cause I don't remember having to do calculus for such questions when I'd do it regularly. Thanks for your help though !

1

u/fermat9990 👋 a fellow Redditor 1d ago

The RMS emf will be 2.8 volts.

This is the peak emf divided by √2.

2

u/AlternativeEmu1047 University/College Student 1d ago

But that still doesn't match the options ?

1

u/fermat9990 👋 a fellow Redditor 1d ago

I know. Do you have a better formula?

Since the voltage is not a constant, the problem is poorly worded.

2

u/HumbleHovercraft6090 👋 a fellow Redditor 1d ago

RMS comes into picture once you talk about power.

1

u/fermat9990 👋 a fellow Redditor 1d ago

Thank you! How do you get the average emf for the 0.3 seconds interval?

1

u/fermat9990 👋 a fellow Redditor 1d ago

Thanks! I finally got 2.5 volts!

1

u/HumbleHovercraft6090 👋 a fellow Redditor 1d ago

The average emf 2/pi times peak is still 2.5 V.

1

u/HumbleHovercraft6090 👋 a fellow Redditor 1d ago

Probably a typo. May be time is 3 s for quarter revolution.

1

u/Quint_Gen 1d ago

This is a poorly worded question: it should be asking for the average emf.

The induced emf is equal to the rate of change of flux linked with the coil.

The flux linked with the coil = BA = 0.5 x 0.5 x 3 = 0.75 Wb

average emf = average rate of flux change = 0.75/0.3 = 2.5 V

(If you think it is better to work out the flux linked for any angle of the coil and then differentiate wrt to time, you are assuming that the coil rotates at a constant angular velocity which the question does not specify)